[libcamera-devel,v6,16/12] fixup! libcamera: transform: Invert operator*() operands
diff mbox series

Message ID 20231022224159.30298-4-laurent.pinchart@ideasonboard.com
State New
Headers show
Series
  • libcamera: Replace CameraConfiguration::transform
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Commit Message

Laurent Pinchart Oct. 22, 2023, 10:41 p.m. UTC
- Simplify documentation

Signed-off-by: Laurent Pinchart <laurent.pinchart@ideasonboard.com>
---
 src/libcamera/transform.cpp | 17 +++++++----------
 1 file changed, 7 insertions(+), 10 deletions(-)

Patch
diff mbox series

diff --git a/src/libcamera/transform.cpp b/src/libcamera/transform.cpp
index 85bc2d28b0cd..0ccdb42fa406 100644
--- a/src/libcamera/transform.cpp
+++ b/src/libcamera/transform.cpp
@@ -193,21 +193,18 @@  Input image   | |   goes to output image   | |
  * \param[in] t0 The first transform to apply
  * \param[in] t1 The second transform to apply
  *
- * Compose two transforms by applying \a t1 after \a t0. The operation
- * is conceptually equivalent to the canonical notion of function composition,
- * with inverse order of operands. If in the canonical function composition
- * notation "f * g" equals to "f(g())", the notation for Transforms composition
- * "t0 * t1" equals to "t1(t0()))" where \a t0 is applied first, then \a t1.
- *
- * For example, `HFlip * Transpose` performs `HFlip` first and then the
- * `Transpose` yielding `Rot270`, as shown below.
+ * Compose two transforms into a transform that is equivalent to first applying
+ * \a t0 and then applying \a t1. For example, `HFlip * Transpose` performs
+ * `HFlip` first and then the `Transpose` yielding `Rot270`, as shown below.
 ~~~
              A-B                 B-A                     B-D
 Input image  | |   -> HFLip ->   | |   -> Transpose ->   | |   = Rot270
              C-D                 D-C                     A-C
 ~~~
- * Note that composition is generally non-commutative for Transforms,
- * and not the same as XOR-ing the underlying bit representations.
+ * Note that composition is generally non-commutative for Transforms, and not
+ * the same as XOR-ing the underlying bit representations.
+ *
+ * \return A Transform equivalent to applying \a t0 and then \a t1
  */
 Transform operator*(Transform t0, Transform t1)
 {